First of all —
— of course, 1 ≠ 0.
One is NOT zero.
If they were similar, blimey! Imagine how the bridge construction would be and how many of us would chew beams.
The steps:
chair ≠ banana
Counterexample: Bob ate a chair yesterday.
Hi, Bob. It was your boardroom meeting suggestion which led to the two-layer right-click menu in Windows 11, innit? ðĪ Or was it meating?
Let's dissect the proof from Mudd Math Fun Facts which yields 1 = 0 — the link is gone now.
Quoted
A bit paraphrased.
It looks fine at first — with a baffling final line.
BUT!
There is a subtle — but actually a MASSIVE — flaw in it.
The Error Occurred at the Division Step
Since x = y, if we use (x - y) as the divisor, that means we're dividing both sides with 0 (zero).
Let's have a look at the the quadratic equation (the dividend) which is being divided:
The part which isn't acceptable is when 0 on both sides are divided also by 0.
${(x² - y²)}/{(x - y)} = {(xy - y²)}/{(x - y)}$
Once again, since $x = y$, hence:
$(x - y) = (x² - y²) = (xy - y²) = 0$
If we substitute the manipulation with the actual values:
❓❓
Meaning, it has NO ACTUAL VALUE.
It's a DEFINITION in mathematics.
indeterminate = indeterminate ⁉️
Not in mathematics, it's indeterminate.
Indeterminate means the expression could represent many possible values depending on context — so we cannot pin down a single answer.
In English (language), in term of sameness, indeed indeterminate is indeterminate, they're the same words — but not in mathematics, as indeterminate is not a value.
For instance:
- Uncertainty A: Will Bob take a shower?
- Uncertainty B: Is that tea poisonous?
We can't say uncertainty A is equal to uncertainty B. ðĪ Even though both are an uncertainty. Well, Bob SchrÃķdinger will and will not take a shower with both poisonous tea and regular tea.
Right. So.
Meaning, it MUST be stopped at the subtraction step.
Other operations (+, -, exponent, root, logarithmic, integral, etc.) besides division can be added, but it will certainly give the same result. That is 0 = 0 (or other same number, 1 = 1, 2 = 2, etc.)
Or, we can do another type of different starting manipulation for those variables ($x$ and $y$), and we'll still be using the 0 division to achieve "$1 = 0$".
In conclusion, the proof manipulation above is a jolly time to check our keenness in algebra and arithmetic. This is categorised under —
— trope.